Tetrabromoethane is a colorless or light yellow liquid with a pungent odor similar to bromine. Its chemical formula is C2H4Br4, CAS 79-27-6. Its density is 2.27 grams per cubic centimeter, boiling point is 198.5 ℃, and melting point is 9.6 ℃. In the molecular structure of tetrabromoethane, four bromine atoms are connected to carbon atoms, forming four bromomethyl units. This structure gives tetrabromoethane high stability in chemical reactions. Tetrabromoethane has a high refractive index and can be used to make optical materials and solvents. It has good solubility and can dissolve various organic substances, making it widely used in industries such as dyes, pesticides, pharmaceuticals, etc. In addition, tetrabromoethane can also be used as a fire extinguishing agent and flame retardant for fire suppression and prevention.
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Tetrabromoethane is an organic compound with relatively stable chemical properties, but it can undergo some chemical reactions under specific conditions.
1. Substitution reaction
The substitution reaction of tetrabromoethane refers to the reaction in which one or more bromine atoms in the tetrabromoethane molecule are replaced by other functional groups. The following are the detailed steps and chemical equations for the substitution reaction of tetrabromoethane:
1.1 Nucleophilic substitution reaction
Nucleophilic substitution reaction refers to the attack of haloalkanes or esters by nucleophilic reagents, resulting in the partial substitution of halogen atoms. In the nucleophilic substitution reaction of tetrabromoethane, nucleophilic reagents (such as sodium alcohol, ammonia, etc.) attack a bromine atom of tetrabromoethane, causing that bromine atom to be replaced by nucleophilic reagents.
Reaction steps:
(1) Nucleophilic reagents attack a bromine atom of tetrabromoethane to form intermediate compounds.
(2) The bromine atoms in intermediate compounds are replaced by nucleophilic reagents, forming substituted products.
(3) Remove hydrogen halide or other protons to produce the final product.
C2H4Br4 + RO- + Br- → C2H4Br3OR + Br-
(where RO- represents nucleophilic reagents such as sodium alcohol)
1.2 Electrophilic substitution reaction
Electrophilic substitution reaction refers to the attack of haloalkanes or esters by electrophilic reagents, resulting in the partial substitution of halogen atoms. In the electrophilic substitution reaction of tetrabromoethane, electrophilic reagents (such as chlorine, bromine, etc.) attack a bromine atom of tetrabromoethane, causing that bromine atom to be replaced by electrophilic reagents.
Reaction steps:
(1) The electrophilic reagent attacks a bromine atom of tetrabromoethane, forming an intermediate compound.
(2) The bromine atoms in intermediate compounds are replaced by electrophilic reagents, forming substituted products.
(3) Remove hydrogen halide or other protons to produce the final product.
C2H4Br4 + X2 → C2H4X2Br2 + 2HBr
(where X represents electrophilic reagents such as chlorine and bromine)
2. Hydrolysis reaction
The hydrolysis reaction of tetrabromoethane refers to the process in which tetrabromoethane reacts with hydroxide in water to remove hydrogen bromide and generate ethylene glycol. The following are the detailed steps and chemical equations for the hydrolysis reaction of tetrabromoethane:
Reaction steps:
(1) Tetrabromoethane forms conjugated acid-base pairs with water
(2) Conjugated acid-base pairs generate bromine ions and ethylene glycol through electron transfer processes
(3) Bromine ions combine with hydroxide ions to generate hydrogen bromide, while ethylene glycol obtains hydrogen ions from water to generate ethylene glycol
C2H4Br4 + 2H2O + 2OH- → C2H6O2 + 4Br- + 2H2O
It should be noted that the hydrolysis reaction of tetrabromoethane requires heating and alkali addition to promote the reaction. At the same time, hydrogen bromide will be generated during the reaction process, and it is necessary to avoid reacting with alkali to avoid affecting the quality and yield of the product.
3. Oxidation reaction
Tetrabromoethane can be oxidized by oxidants, such as when co heated with silver nitrate aqueous solution and sodium hydroxide aqueous solution, hydrogen bromide can be removed to form glyoxal. Oxidation reaction refers to the process of tetrabromoethane losing bromine atoms under the action of an oxidant. The following are the detailed steps and chemical equations for the oxidation reaction of tetrabromoethane:
(1) Tetrabromoethane reacts with oxidants such as silver nitrate and hydrogen peroxide to form intermediate compounds.
(2) The bromine atoms in intermediate compounds are oxidized by oxidants to form other compounds.
(3) Remove hydrogen bromide or other products to generate the final oxidation product.
C2H4Br4 + 2NaOH + HNO3 → C2H4O2 + 4NaBr + H2O
4. Reduction reaction
Tetrabromoethane can be reduced by reducing agents, such as when reacting with metallic sodium in liquid ammonia, hydrogen bromide can be removed to produce ethane.
The reduction reaction of tetrabromoethane refers to the process of reducing tetrabromoethane to ethane through a reducing agent. The following are the detailed steps and chemical equations for the reduction reaction of tetrabromoethane:
(1) Tetrabromoethane reacts with reducing agents such as hydrogen and sodium to form intermediate compounds.
(2) The bromine atoms in intermediate compounds are reduced by reducing agents to produce ethane.
(3) Remove hydrogen bromide or other products to generate the final reduction product.
C2H4Br4 + 4H2 → C2H6 + 4Br-
(where H2 represents hydrogen)
5. Hydrogenation reaction
The hydrogenation reaction of tetrabromoethane refers to the process of reducing tetrabromoethane to ethane through a hydrogenation reducing agent. The following are the detailed steps and chemical equations for the hydrogenation reaction of tetrabromoethane:
(1) Tetrabromoethane reacts with hydrogenation reducing agents (such as hydrogen, formaldehyde, etc.) to form intermediate compounds.
(2) The bromine atoms in intermediate compounds are reduced by hydrogenation reducing agents to produce ethane.
(3) Remove hydrogen bromide or other products to generate the final reduction product.
C2H4Br4 + 4H2 → C2H6 + 4Br-
(where H2 represents hydrogen)
6. Cracking reaction
The cracking reaction of tetrabromoethane is usually carried out under high temperature conditions, which is related to the cracking reaction. The following are the detailed steps and chemical equations for the cracking reaction of tetrabromoethane:
(1) Tetrabromoethane undergoes pyrolysis reaction under high temperature conditions, producing ethylene and hydrogen bromide.
(2) Ethylene further fractures at high temperatures, producing methane and hydrogen bromide.
(3) Methane and hydrogen bromide continue to react to produce hydrogen and bromomethane.
C2H4Br4 → C2H4 + 4Br- (this is the first step reaction)
C2H4 → CH4 + Br2 (this is the second and third step reaction)
7. Reactions with metals
The reaction between tetrabromoethane and metals usually involves nucleophilic substitution reactions, where metals act as nucleophilic reagents to attack the bromine atoms of tetrabromoethane and lead to substitution reactions. The following are the detailed steps and chemical equations for the reaction of tetrabromoethane with metals:
(1) Metal acts as a nucleophilic reagent to attack a bromine atom of tetrabromoethane, forming an intermediate compound.
(2) The bromine atoms in intermediate compounds are replaced by nucleophilic reagents, forming substituted products.
(3) Remove hydrogen bromide or other products to generate the final substituted product.
C2H4Br4 + R-M → C2H4Br3-R + R-M-Br
(where R represents alkyl or aryl group and M represents metal)
8. Reaction with acid
The reaction between tetrabromoethane and acid usually involves a nucleophilic substitution reaction, where the acid acts as a nucleophilic reagent to attack the bromine atom of tetrabromoethane and lead to a substitution reaction. The following are the detailed steps and chemical equations for the reaction of tetrabromoethane with acid:
(1) Acids act as nucleophilic reagents to attack a bromine atom of tetrabromoethane, forming intermediate compounds.
(2) The bromine atoms in intermediate compounds are replaced by nucleophilic reagents, forming substituted products.
(3) Remove hydrogen bromide or other products to generate the final substituted product.
C2H4Br4 + R-COOH → C2H4Br3-R + R-COOH-Br
(where R represents alkyl or aryl)